All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Curious Real Additive Relationship (Posted on 2008-04-12) Difficulty: 2 of 5
Are there any non zero real triplet(s) (p, q, r) that satisfy the following system of equations?

p + 1/p = q, q + 1/q = r, and r + 1/r = p

If such triplet(s) exist, find at least one of these. Otherwise, prove that no such triplet can conform to the given conditions.

  Submitted by K Sengupta    
Rating: 3.0000 (2 votes)
Solution: (Hide)
No such triplet can conform to the given conditions.

EXPLANATION:

I. Refer to the solution submitted by Dennis in this location.

II. Refer to the solution submitted by Charlie in this location.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: alternate solutionK Sengupta2008-05-05 14:45:40
re: solutionK Sengupta2008-05-05 14:43:15
Solutionalternate solutionDennis2008-04-12 20:51:13
SolutionAccept no substitutesSteve Herman2008-04-12 20:25:36
SolutionsolutionCharlie2008-04-12 14:26:33
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information