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Sequence Group II (Posted on 2008-07-21)

Four positive integers P, Q, R and S with P < Q < R < S are such that P, Q and R (in this order) are in arithmetic sequence and Q, R and S (in this order) are in harmonic sequence.

Given that S - P = 19, determine all possible quadruplet(s) (P, Q, R, S) that satisfy the given conditions.

Submitted by K Sengupta

Rating: 4.0000 (1 votes)

Solution: (Hide)

(P, Q, R, S)= (72, 78, 84, 91) is the only possible solution.

For an explanation, refer to the solution submitted by Praneeth in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
re: Solution	K Sengupta	2008-08-05 12:12:01
Solution	Praneeth	2008-07-22 06:05:41
Possible Solution	Dej Mar	2008-07-22 04:02:43

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