All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Subtract 1 from squared abbbb (Posted on 2008-08-16) Difficulty: 3 of 5
Determine all possible five digit positive decimal (base 10) integer(s) of the form abbbb, with a ≠ b, that contain no leading zeroes, such that (abbbb2 - 1) is equal to a positive ten digit integer (with no leading zeroes) containing each of the digits 0 to 9 exactly once.

Note: While the solution may be trivial with the aid of a computer program, show how to derive it without one.

  Submitted by K Sengupta    
Rating: 4.0000 (1 votes)
Solution: (Hide)
855552 − 1 = 7319658024, and 977772 − 1 = 9560341728 are the only possible solutions.

For an explanation, refer to the solution submitted by Ady TZIDON here, and by Daniel here.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: analytical and briefK Sengupta2008-08-25 13:05:36
re: Analytical Solution (spoiler)K Sengupta2008-08-25 13:04:45
SolutionYes, it's trivial with a computer programCharlie2008-08-17 13:35:13
Solutionanalytical and briefAdy TZIDON2008-08-17 10:24:23
Analytical Solution (spoiler)Daniel2008-08-16 15:29:36
A start (spoiler)Steve Herman2008-08-16 15:20:25
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information