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Subtract 1 from squared abbbb (Posted on 2008-08-16) |
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Determine all possible five digit positive decimal (base 10) integer(s) of the form abbbb, with a ≠ b, that contain no leading zeroes, such that (abbbb2 - 1) is equal to a positive ten digit integer (with no leading zeroes) containing each of the digits 0 to 9 exactly once.
Note: While the solution may be trivial with the aid of a computer program, show how to derive it without one.
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Submitted by K Sengupta
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Rating: 4.0000 (1 votes)
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Solution:
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(Hide)
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855552 − 1 = 7319658024, and 977772 − 1 = 9560341728 are the only possible solutions.
For an explanation, refer to the solution submitted by Ady TZIDON here, and by Daniel here.
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