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No. of Distinct Solutions(2) (Posted on 2008-07-14) |
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If x,y,z are non-negative integers, find the number of distinct solutions for the following equation:
2x2+y2+z2+2xy+2xz-32x-12y-20z+136=0.
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![Solution Solution](/images/perplexus/icons/solution.gif) | Solution | K Sengupta | 2008-07-14 10:42:49 |
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