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Some Reals Sum Two (Posted on 2008-09-01) |
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Determine all possible real quadruplet(s) (P, Q, R, S) with P ≤ Q ≤ R ≤ S that satisfy this system of equations:
P + Q*R*S = 2, and:
Q + R*S*P = 2, and:
R + P*Q*S = 2, and:
S + P*Q*R = 2.
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Submitted by K Sengupta
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Rating: 5.0000 (1 votes)
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Solution:
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(Hide)
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(P,Q,R,S) = (1,1,1,1) and (-1,-1,-1,3).
EXPLANATION:
Refer to the methodologies submitted by Daniel and Steve Herman in the first two comments.
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