perplexus.info :: Just Math : Going maximum with factorial(s)

Going maximum with factorial(s) (Posted on 2008-10-24)

Consider all possible positive integer(s) M ≥ 5, such that (M)! is expressible as the product of (M-3) consecutive positive integers. For example, we observe that: 6! = 8*9*10 .

Determine the maximum value of M.

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

The required maximum value of M is 23.
For an explanation, refer to the solution submitted by Charlie in this location, and its rejoinder in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
algebraic exploration (proof?)	Charlie	2008-10-24 13:11:27
computer exploration (spoiler? -- UBASIC program)	Charlie	2008-10-24 12:34:10

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