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The Civic Club (Posted on 2009-02-14) Difficulty: 3 of 5
There is a civic club in town with fewer than 100 members. Here are some of its statistics:

To the nearest whole percent:

28% are former committee members.
29% are current committee members.
42% have never been on a committee.

Also, 35% of the former committee members are women, again to the nearest whole percent.

How many members does the club have and how many are in each category mentioned above?

  Submitted by Charlie    
Rating: 2.6667 (3 votes)
Solution: (Hide)
The club has 92 members, divided according to the table below. The table shows how best to get the anomalous total percentage for a given number of members. However any given distribution can be multiplied for larger numbers, so the higher numbers have no real significance in terms of limiting possibilities.
former current never women total
                       in
                     former
                      group
                      
26       27      39     9    92
31       32      46    11   109
37       38      55    13   130
43       44      64    15   151
43       45      65    15   153
46       48      69    16   163
48       50      72    17   170
49       50      73    17   172
49       51      73    17   173
51       52      76    18   179
51       53      76    18   180
52       54      78    18   184
54       56      80    19   190
54       56      81    19   191
55       56      82    19   193
55       57      82    19   194
57       59      85    20   201
60       62      89    21   211
60       62      90    21   212
62       64      92    22   218
63       65      94    22   222
65       67      97    23   229
69       71     103    24   243


DEFDBL A-Z
PRINT
FOR memb = 4 TO 10000
  f = memb * .28
  c = memb * .29
  n = memb * .42
  FOR former = INT(f) TO -INT(-f)
  FOR current = INT(c) TO -INT(-c)
  FOR never = INT(n) TO -INT(-n)
   w = former * .35
   FOR women = INT(w) TO -INT(-w)
    pctF = INT(100 * former / memb + .5)
    pctC = INT(100 * current / memb + .5)
    pctN = INT(100 * never / memb + .5)
    pctW = INT(100 * women / former + .5)
    IF pctF = 28 AND pctC = 29 AND pctN = 42 AND pctW = 35 THEN
     IF former + current + never = memb THEN
      PRINT former; current; never; women, memb
     END IF
    END IF
   NEXT
  NEXT
  NEXT
  NEXT

NEXT

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Puzzle Thoughts K Sengupta2023-09-22 22:15:07
SolutionsolutionDej Mar2009-02-14 19:39:50
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