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Sequence with only 3 numbers (Posted on 2009-03-07) |
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Trying to define a way to generate the terms of a sequence, and starting with the number 5, I found, surprisingly, that the way I used generated this sequence:
5, 8, 11, 5, 8, 11, 5, 8, 11, ...
And these 3 numbers repeat in this order indefinitely.
Define a simple way to generate this sequence.
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Submitted by pcbouhid
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Rating: 2.0000 (1 votes)
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Solution:
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(Hide)
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My simple way was:
square the previous one, add the digits, plus 1.
Watch this:
2, 5, 8, 11,... 3, 10, 2, 5, 8, 11,... 4, 8, 11, 5, 8, 11,... 6, 10, 2, 5, 8, 11,... 7, 14, 17, 20, 5, 8, 11,... 22, 17, 20, 5, 8, 11,... etc...
That is, no matter the "seed", I always get the periodic 5, 8, 11!!!!!
This can be proved? I didnīt find (yet) a counterproof!! |
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