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Primes and Squares (Posted on 2009-08-16)

Determine all possible triplet(s) (P, Q, R) of nonnegative integers, with P ≥ Q, such that each of P² + 1 and Q² + 1 is a prime, and: (P² + 1)(Q² + 1) = (R² + 1).

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

P=1, Q=2, R=3 is the olny possible solution.
For an explanation, refer to the solution submitted by armando in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
No way?	armando	2016-02-06 18:02:12
Thoughts	Brian Smith	2016-02-06 13:46:57
computer exploration	Charlie	2009-08-16 16:50:32

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