Home > Probability
| Sum (Pair Product) = Sum (Triplet Product) (Posted on 2009-11-08) |
 |
Determine the probability that for a positive integer N chosen at random between 1000 and 9999 inclusively, the sum of the products of pairs of digits in N is equal to the sum of products of triplets of its digits.
|
|
Submitted by K Sengupta
|
|
Rating: 4.0000 (1 votes)
|
|
|
Solution:
|
(Hide)
|
The required probability is 51/9000 = 17/3000 = 0.5667 0.00566 (approx.)
For a detailed explanation, refer to the solution submitted Dej Mar in this location.
|
Comments: (
You must be logged in to post comments.)
|
|
Please log in:
Forums (0)
Newest Problems
Random Problem
FAQ |
About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
|
