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Permute 2 Power (Posted on 2009-11-18) |
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Prove that there does not exist any positive integer N which is a power of 2 such that the digits of N (in the base ten representation) can be permuted to form a different power of 2. It is known that neither N nor any of the permutations of the digits of N can contain any leading zero.
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Submitted by K Sengupta
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Rating: 5.0000 (1 votes)
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Solution:
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(Hide)
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Refer to the solution submitted by Charlie in this location. |
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