perplexus.info :: Numbers : Perfect Squares Given

Perfect Squares Given (Posted on 2010-08-17)

Substitute each of the capital letters in bold by a different base ten digit from 0 to 9 such that each of EEN, VIER and NEGEN is a perfect square. None of the numbers can contain any leading zero.

Disregarding the non leading zero condition, if we additionally impose the restriction that GIVEN is divisible by 23, then what will be the corresponding substitution?

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

Disregarding the leading zero restriction- the two solutions to the alphametic is as follows:
E V I N G 0 2 6 4 8 4 3 2 1 6
Therefore:
(1) Imposing the non-leading zero restriction- we have:
EEN = 441, VIER = 3249, NEGEN = 14641
(2) EEN = 004, VIER= 2601, NEGEN = 40804
86204= 3748*23, so that:
GIVEN = 86204 is divisible by 23.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
answers	Dej Mar	2010-08-18 03:08:06
split second	ed bottemiller	2010-08-17 15:12:56
answers- spoiler	Ady TZIDON	2010-08-17 12:36:55

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