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| Sum (Squares) = Prime Number (Posted on 2010-09-09) |
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Each of A, B and C is a prime number with A ≤ B ≤ C.
Determine all possible triplet(s) (A, B, C) such that:
(i) A2 + B2 + C2 is a prime number, and:
(ii) C6 does not leave a remainder of 1 when divided by 14.
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Submitted by K Sengupta
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Rating: 4.0000 (2 votes)
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Solution:
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(Hide)
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(A,B,C)= (3,3,7), (3,5,7), and (3,7,7)
For an explanation, refer to the solution posted by Daniel in this location.
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