perplexus.info :: Geometry : Distance = Inradius

Distance = Inradius (Posted on 2010-10-14)

M is the midpoint of the side BC of triangle ABC, the center of whose incircle is denoted by O. AH is perpendicular to BC, and the line MO intersects AH at the point E. It is known that: |AB| ≠ |AC|.

Prove that the distance AE is equal to the radius of the incircle.

Submitted by K Sengupta

Rating: 3.5000 (2 votes)

Solution: (Hide)

Reger to the solution submitted by Bractals in this location.

Comments: ( You must be logged in to post comments.)

	Subject	Author	Date
	Solution	Bractals	2010-10-14 15:43:33

Please log in:

Login:
Password:
Remember me:

Sign up! \| Forgot password

Search:

Search body:

Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info