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TriNRect (Posted on 2010-10-13) Difficulty: 2 of 5
 
Let R be the area of rectangle ABCD and
T the area of triangle APQ (where P and
Q are points on sides BC and CD of ABCD respectively).

What is the minimal value of |BP|+|DQ|
in terms of R and T?

Note: R and T are constants with 0 < T ≤ R/2.
Therefore, |BP| and |DQ| are not independent variables
(i.e. if P varies between B and C, then Q
must vary between C and D such that T
stays constant).  

  Submitted by Bractals    
Rating: 5.0000 (1 votes)
Solution: (Hide)
Let w = |AB|, x = |BP|, y = |DQ|, and z = |AD|.
Let [FG...KL] denote the area of polygon FG...KL.
Then

    [ABCD] = [APQ] + [ABP] + [ADQ] + [CPQ]

        or

    R = T + ½wx + ½yz + ½(w-y)(z-x)

        or

    xy = R - 2T

To minimize the value of |BP|+|DQ| = x + y,

we let x = y and get

        2√(R-2T).

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Puzzle ThoughtsK Sengupta2024-05-21 09:37:03
Thanksxdog2010-10-14 20:45:33
re: solution. minor correctionJer2010-10-14 15:15:37
solutionxdog2010-10-14 13:28:29
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