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How Many ? (Posted on 2004-01-02) |
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How many positive integers 'n' are there such that [(2)^n + 1] is divisible by 7 ?
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Submitted by Ravi Raja
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Rating: 2.6667 (9 votes)
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Solution:
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(Hide)
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2^(3) = 1 (mod 7). Hence 2^(3m) = 1 (mod 7), 2^(3m+1) = 2 (mod 7), and 2^(3m+2) = 4 (mod 7). Hence we never have 7 dividing 2^n + 1, and 7 divides 2^n - 1 iff 3 divides n.
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