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Digit addition and insertion (Posted on 2011-10-27) Difficulty: 2 of 5
(I) Determine all possible base ten 8-digit perfect square(s) N, with no leading zeroes, such that the number obtained by increasing the second digit (reading left to right) of N by 1 is also a perfect square.

(II)Determine all possible base ten 4-digit perfect square(s) N, with no leading zeroes, such that the number obtained by inserting two zeroes between the thousands digit and the hundreds digit of N is also a perfect square.

**** Calculators are allowed, but no computer programs.

  Submitted by K Sengupta    
Rating: 5.0000 (2 votes)
Solution: (Hide)
(I) 24502500 = 49502 :: 25502500 = 50502
38564100 = 62102 :: 39564100 = 62902

If wrap-around of digits is allowed so that 9 is incremented to 0, then:

29702500 = 54502 and 20702500 = 45502

If, however, when you do this you also carry the 1 from what's actually a 10, you get:

99500625 = 99752 and 100500625 = 100252

(II) 2704 = 522 :: 200704 = 4482
7569 = 872 :: 700569 = 8372

Comments: ( You must be logged in to post comments.)
  Subject Author Date
No SubjectK Sengupta2023-08-05 12:31:01
supplement manufacturersBradley Bauer2023-08-05 04:45:39
MentalBradley Bauer2023-07-26 07:02:26
x3diamondBradley Bauer2023-07-26 06:49:19
8Bradley Bauer2023-07-26 06:27:36
7Bradley Bauer2023-07-26 06:09:41
6Bradley Bauer2023-07-26 05:51:41
5Bradley Bauer2023-07-26 05:34:05
4Bradley Bauer2023-07-26 05:14:41
re(2): answersKevin2022-01-31 10:07:01
re: answersCharlie2011-10-27 18:31:11
SolutionanswersDej Mar2011-10-27 12:32:53
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