![](/images/dot.gif)
Home > Numbers
As easy as 123 (Posted on 2013-10-25) |
|
In the multiplication of two 3-digit numbers, all digits
Except 1,2, and 3 were either erased or were not initially a part of the process.
Fill in the missing digits if 3EE*EEE=2E11E1 and the partial products (in some order) were: 2EE2, 2EE3, and 3321.
|
Submitted by Ady TZIDON
|
No Rating
|
|
Solution:
|
(Hide)
|
3321 is factorized 9*369, ,the only way to get 3 digit multiplicand i.e. 369
the rest easily follows, leading to 369*789=291,141/ |
Comments: (
You must be logged in to post comments.)
|
![](/images/dot.gif) |
Please log in:
Forums (0)
Newest Problems
Random Problem
FAQ |
About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
|