perplexus.info :: Just Math : 2015 digits

2015 digits (Posted on 2014-09-04)

A string of 2015 digits starts with a "4". Any number formed by two consecutive digits is divisible by either 19 or 23.

What is the last digit in this sequence?

What if the sequence had 2016 digits?

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

The required last digit is 9.
If the sequence had 2016 digits, th elast digit can either be 2, or 5.
For an explanation, refer to the solution submitted by Charlie in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
solution	Charlie	2014-09-04 11:22:35
solution	Ady TZIDON	2014-09-04 10:18:02

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