Inconsiderable Integer Illation (Posted on 2014-11-16)

           cos 96o + sin 96o
tan 19No = -----------------
           cos 96o - sin 96o

	Submitted by K Sengupta
Rating: 5.0000 (2 votes)
Solution:	(Hide)
Multiplying each of the numerator and denominator by 1/√2,=sin 45o= cos 45o, we have: tan 19No = sin(96+45)/cos(96+45) = sin 141o/cos 141o tan 19No = tan 141o = tan (141+180*k) For k=16 we observe that 141+180k is divisible by 19, rendering 3021/19= 159 as the required minimum value of N.

	Subject	Author	Date
	solution	Ady TZIDON	2014-11-17 09:35:26
	re: Hint	Ady TZIDON	2014-11-17 07:45:11
	Hint	K Sengupta	2014-11-17 07:31:21
	re(3): Actual answer -- calculator solution	Ady TZIDON	2014-11-17 03:01:35
	re(2): Actual answer -- calculator solution	Jer	2014-11-16 22:26:01
	re: Actual answer -- calculator solution	Ady TZIDON	2014-11-16 15:41:51
	re: answer only	Kenny M	2014-11-16 14:56:37
	re: answer only	Charlie	2014-11-16 14:55:12
	Actual answer -- calculator solution	Charlie	2014-11-16 14:50:58
	answer only	Ady TZIDON	2014-11-16 11:01:54