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| Nil Carry Nuance (Posted on 2014-12-04) |
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Consider the set S ={1000, 1001, ...., 2013, 2014}.
For how many pairs of consecutive integers in S is no carrying required when the two integers are added?
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Submitted by K Sengupta
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Rating: 5.0000 (1 votes)
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Solution:
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(Hide)
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The required number of pairs of consecutive integers is 166.
For an explanation, refer to the solution submitted by tomarken in this location.
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Subject |
Author |
Date |
 | Solution | tomarken | 2014-12-04 07:56:29 |
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