In general the probability of the first digit being below Z is
the integral from 0 to 1 of the function Z/10^(1/X)dX
which in closed form is
Z/10-ln(Z/10)*Ei(Z/10)
Where Ei is the exponential integral function.
The approximate distribution:
p(Z=0)=.025429
p(Z=1)=.037574
p(Z=2)=.047483
p(Z=3)=.057748
p(Z=4)=.069300
p(Z=5)=.083129
p(Z=6)=.100802
p(Z=7)=.125497
p(Z=8)=.165948
p(Z=9)=.287099
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