All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Quadratic and Five Variable Query (Posted on 2015-12-20) Difficulty: 3 of 5
Find real numbers A,B,C,D and E that satisfy this system of equations:

(A-B+C)2 = B(D+E-B), and:
(B-C+D)2 = C(E+A-C), and:
(C-D+E)2 = D(A+B-D), and:
(D-E+A)2 = E(B+C-E), and:
(E-A+B)2 = A(C+D-A)

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts Thoughts Comment 2 of 2 |
By adding all the equations together and simplifying I got the result:
A^2+B^2+C^2+D^2+E^2 = A*B+B*C+C*D+D*E+E*A

I tried a few cases assuming two of the variables were equal and kept coming to the conclusion that all five were then equal.  So I suspect the trivial solution is the only solution.
  Posted by Brian Smith on 2016-07-10 19:52:38
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (16)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information