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Complex Number Query (Posted on 2016-04-03) Difficulty: 3 of 5
Determine all possible values of a complex number z such that:
(3z+1)(4z+1)(6z+1)(12z+1) = 2

No Solution Yet Submitted by K Sengupta    
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Solution Solution (probably the hard way) Comment 1 of 1
There's probably a more clever method than just multiply out, set to zero, and re-factor.  But it worked.  I'd like to see a better way, but this was a nice diversion.

The product is
set to zero

I figured if this is solvable its probably the product of two quadratics so I decided to try factoring by hand as
which leads to the system

solving for b gives
which only has a few solutions with positive integer for a and only one of these gives positive integers for the rest.  The factorization sought is:


and the quadratic formula finishes us off.  The solutions are:

(-5±i√23)/24 and (-5±√33)/24
  Posted by Jer on 2016-04-03 20:19:34
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