A positive integer is expressible as 3X1 in base B and 1X3 in base B+6, where X is a base B (and also base B+6) digit.
Find all values of B and X.
Prove that no further solution is possible.
*** Of course, B is a positive integer.
X=7, B=10 So 371=1*256+7*16+3=256+112+3
** does not merit d3
*** solved by comparing 3b^2 +b*x+1 and (b+6)^2+(b+6)*x+3
Edited on May 2, 2016, 1:10 pm