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Hundred Product Hinder (Posted on 2016-06-13) Difficulty: 3 of 5
N is a positive integer and D(N) denotes the total number of positive divisors of N (including 1 and N).

Find all N such that: N = 100*D(N).

No Solution Yet Submitted by K Sengupta    
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A candidate | Comment 1 of 2
With a minimal of reason and some brute force I find a candidate:

2000 has 20 divisors. 

  Posted by armando on 2016-06-13 14:27:11
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