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Fibonacci Determinant (Posted on 2016-04-19) Difficulty: 3 of 5
A size n determinant has all 1s on the main diagonal and the first superdiagonal. It has all -1s on the first subdiagonal. It has zeros in all other places.

Show that this determinant evaluates to Fibonacci number F(n+1).

The determinant corresponding to n=5 is depicted below:
 | 1  1  0  0  0 |
 |-1  1  1  0  0 |
 | 0 -1  1  1  0 | = 8 = F(6)
 | 0  0 -1  1  1 |
 | 0  0  0 -1  1 |

See The Solution Submitted by Brian Smith    
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  Subject Author Date
Visual solutionarmando2016-04-19 11:23:17
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