x^2 + 2yz+ 5x = 2
y^2 + 2zx+ 5y = 2
z^2 + 2xy+ 5z = 2
Pen and paper only, please.
(In reply to re: Solution
by Steve Herman)
Formally, I agree, although my intention was to ask for integer solutions only.
My opinion still is that the title, usually related to problem's text, implies integer triplets only.
Nothing is wrong, as long as we understand each other, in broadening the scope of the post, once the primary conditions are defined.
Liking (meaning preferring) or not is immaterial if you conceive that the solver acted following his own assumptions.
Within a couple of days I will publish the "official" solution mentioning both approaches.