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Inequality with a constraint (Posted on 2017-03-04) Difficulty: 4 of 5
Assume x,y,z positive real numbers that satisfy x≤1, y≤2, x+y+z=6. Prove that (x+1)(y+1)(z+1)≥4xyz.

Source: Published by Marius Stanean, Romania, without a solution, in the Mathematical Reflections, Number 1, 2013 (Problem J258).

No Solution Yet Submitted by Ady TZIDON    
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