All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Inequality with a constraint (Posted on 2017-03-04) Difficulty: 4 of 5
Assume x,y,z positive real numbers that satisfy x≤1, y≤2, x+y+z=6. Prove that (x+1)(y+1)(z+1)≥4xyz.

Source: Published by Marius Stanean, Romania, without a solution, in the Mathematical Reflections, Number 1, 2013 (Problem J258).

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( You must be logged in to post comments.)
  Subject Author Date
There are no comments yet.
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (12)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information