All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
It's obvious, but needs proof (Posted on 2017-03-15) Difficulty: 2 of 5
Let points A, B, and C be equally spaced around a circle, and let point P lie on the arc between A and B.

Prove that PA + PB = PC.

See The Solution Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution | Comment 1 of 2

Ptolemy's theorem gives

   PC*AB = PA*BC + PB*CA

Points A, B, and C equally spaced
around the circle gives

   AB = BC = CA


   PC = PA + PB


  Posted by Bractals on 2017-03-17 15:17:05
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2019 by Animus Pactum Consulting. All rights reserved. Privacy Information