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Red vs Black Cuts (Posted on 2017-06-05) Difficulty: 3 of 5
A deck of 52 cards is shuffled and cut into two halves of 26 cards each. What is the probability that the number of red cards (hearts and diamonds) in the first half is equal to the number black cards (clubs and spades) in the second half?

Two jokers are added to the deck. The deck of 54 cards is shuffled and cut into two halves of 27 cards each. Now what is the probability that the number of red cards in the first half is equal to the number black cards in the second half?

  Submitted by Brian Smith    
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Solution: (Hide)
For the deck of 52 cards the probability is 1.
For the deck of 54 cards the probability is 27/53.
Several solutions are posted in the comments.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionAnother way of approaching ithoodat2017-06-12 13:27:03
SolutionsolutionCharlie2017-06-05 10:43:06
re(3): SolutionDaniel2017-06-05 10:28:01
re(2): SolutionJer2017-06-05 09:51:37
re: solutionDaniel2017-06-05 09:40:27
re: SolutionDaniel2017-06-05 09:37:22
SolutionSolutionJer2017-06-05 09:29:12
solutionDaniel2017-06-05 09:26:17
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