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Like CABACB (Posted on 2017-10-08) Difficulty: 4 of 5
Let q(ltr) represent a numerical value of the position in English alphabet of the letter ltr (ltr being one of the letters in ABC}.
So q(A)=1 , q(B)=2 , …q(K)=11 , …q(Z)=26.

Let's take 2k letters, 2 of each of the first k letters of the English ABC.
Now create a string in which between each of the identical letters say each of ltr there are q(ltr) other letters. The title string and its reversal - qualify as such concatenations for k=3.

Not for every k such solutions exist (try e.g. for k=5...).

It is impossible to create such a string for k=26 (either trust me or explain why), but adding one extra symbol, say #,- which will be counted as a letter with q(#)=0 - it can be done (try for k=5 as well)

Solve for k=26 adding "#" to 2*"ABC string".

No Solution Yet Submitted by Ady TZIDON    
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  Subject Author Date
SolutionA solution for k=26Jer2017-10-09 13:25:55
Some Thoughtspossible k's. k=26 not solved.Jer2017-10-09 11:34:59
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