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 Solution's forecast (Posted on 2017-10-24)
Prove that in the set of the equations

(i) x+y+z=a
(ii) 1/x+1/y+1/z=1/a

all possible solutions contain value a as an answer
for one of the uknowns.

 Submitted by Ady TZIDON No Rating Solution: (Hide) GIVEN :(x+y) = (a-z) Transform the 2nd equation into (x+y)/xy + 1/z = 1/a. Substitute for (x+y) and simplify into az(a-z) + xy(a-z) = 0 i.e. ( a-z)(az+xy)= 0 with z=a being a candidate answer. By symmetry we could get x=a or y=a in the same way. QED

Comments: ( You must be logged in to post comments.)
 Subject Author Date solution xdog 2017-10-25 12:07:23 re: Sollution Ady TZIDON 2017-10-25 06:58:01 Sollution Kenny M 2017-10-24 17:06:56
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