All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Magic triangles (Posted on 2018-01-18) Difficulty: 3 of 5
Imagine a triangle ABC with 3 distinct non-zero digits assigned to each of its vertices, say A=1 B=4 C=7.
Now place the six remaining digits, 2 per side, trying to get a sum of 20.
If we place 6 and 9 between A and B the sum on AB will be 1+6+9+4=20
as requested, but the sequel will in no way create a sum of 20 per side.
The above example was given just to illustrate the process.

What are the triplets (A,B,C) that allow fulfilling the required task?
How many distinct generic solutions (define) are there?

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Some Thoughtsre: spoiler.....SQUARES AS WELLAdy TZIDON2018-01-20 17:15:18
spoilerxdog2018-01-18 08:47:20
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information