For each positive integer n, let Mn be the square matrix (nxn) where each diagonal entry is 2018, and every other entry is 1.
Determine the smallest positive integer n (if any) for which the value
of det(Mn) is a perfect square.
(In reply to
n = 4 is a square, regardless of "d" by Steven Lord)
am I missing something? Check this link
http://www.wolframalpha.com/input/?i=Det%5B%7B%7Bx,1,1,1%7D,%7B1,x,1,1%7D,%7B1,1,x,1%7D,%7B1,1,1,x%7D%7D%5D
it would seem to suggest your formulas are off. If my understanding is correct then I think a general formula would be
(d-1)^(n-1)*(d+n-1)
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Posted by Daniel
on 2018-06-15 12:18:31 |
re: n = 4 is a square, regardless of
