All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math > Calculus
Calculus in the interval (Posted on 2019-03-28) Difficulty: 3 of 5
For a twice differentiable function f(x), g(x) is defined as g(x)=(f'(x))2 + f(x)f''(x). For constants a < b < c < d < e, we have f(a)=0, f(b)=2, f(c)=-1, f(d)=2, f(e)=0.

Find the minimum number of roots of the equation g(x)=0 in the interval (a, e).

No Solution Yet Submitted by Danish Ahmed Khan    
No Rating

Comments: ( You must be logged in to post comments.)
  Subject Author Date
There are no comments yet.
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2021 by Animus Pactum Consulting. All rights reserved. Privacy Information