All about
flooble
|
fun stuff
|
Get a free chatterbox
|
Free JavaScript
|
Avatars
perplexus
dot
info
Home
>
Just Math
How many choices? (
Posted on 2019-02-05
)
Polynomial p(x) has integer coefficients and p(3)=−2.
For what values n may it be possible for (x-n) to be a factor of p(x)?
Inspired by
16 choices
See The Solution
Submitted by
Brian Smith
No Rating
Comments: (
You must be logged in to post comments.
)
Subject
Author
Date
Solution
armando
2019-02-10 03:30:51
Please log in:
Login:
Password:
Remember me:
Sign up!
|
Forgot password
Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ
|
About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
blackjack
flooble's webmaster puzzle
Copyright © 2002 - 2024 by
Animus Pactum Consulting
. All rights reserved.
Privacy Information