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Cube rooted till 2019 (Posted on 2019-10-23) Difficulty: 3 of 5
Find the floor of the given expression:

1/(1)1/3+1/(2)1/3+1/(3)1/3+...+1/(2019) 1/3

No Solution Yet Submitted by Danish Ahmed Khan    
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Solution computer summation--spoiler | Comment 1 of 3
Text1.Text = ""
 crlf = Chr$(13) + Chr$(10)
 
 For i = 1 To 2019
   tot = tot + 1 / i ^ (1 / 3)
 Next
 
 Text1.Text = Text1.Text & crlf & tot & " done"
  
finds the total is approximately 238.682009915018, making the floor 238.

UBASIC's

    5   point 20:open "cubrootd.txt" for output as #2
   10   for I=1 to 2019
   20     T=T+1/I^(1/3)
   30   next
   40   print T
   50   print #2,T
   60   close #2

finds a more precise total
 238.682009915017824170857522851591565521186711680291402285179209866264304944641230535568916122204166 

but still leaves the answer (the floor function) 238.

  Posted by Charlie on 2019-10-23 13:17:47
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