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Functional Equation (Posted on 2020-12-22) Difficulty: 3 of 5
Find all funtions f:R->R such that f(xy-1)+f(x)f(y)=2xy-1 for all reals x and y.

No Solution Yet Submitted by Danish Ahmed Khan    
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re: Solution? Comment 2 of 2 |
(In reply to Solution? by Larry)

I agree f(0) needs to be 0.  But then from (1,1): f(0) + f(1)^2 = 1, couldn't f(1)=-1?  


Then f(1) + f(1)*f(2) = 3 makes f(2)=-4, and then f(2)+f(1)f(3) = 5 makes f(3)=-9, ...

So then f(x) = -x^2 also looks like a solution.

  Posted by Brian Smith on 2020-12-23 21:23:43
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