A circumference was divided in n equal parts. On each of these parts one number from 1 to n was placed such that the distance between consecutive numbers is always the same. Numbers 11, 4 and 17 were in consecutive positions. In how many parts was the circumference divided?
For any circular placement of N consecutive numbers where the step value is a constant 'C', the adjacent numbers will either increase by C or decrease by (NC).
In our case, we are going 11 to 4 to 17 which is down 7 then up 13, so N = 7+13 = 20

Posted by Larry
on 20201221 10:37:14 