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Simple set (Posted on 2022-04-25) Difficulty: 2 of 5
Solve:

x*(x+y+z)=1
y*(x+y+z)=2
z*(x+y+z)=6

No Solution Yet Submitted by Ady TZIDON    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Short and Sweet | Comment 1 of 2
Adding the 3 equations, we have:
(x+y+z)^2 =1+2+6=9
(x+y+z)=+/-3   ......(#)
Dividing each of the given equations by (#), we have:
(x,y,z) = (1/3, 2/3, 2), (-1/3, -2/3, -2)



  Posted by K Sengupta on 2022-04-25 08:12:28
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