The great Dudeney, bless his soul, created, inter alia, the following puzzle:
There was a man who lived on a XXXX street numbered 1,2,3 … etc. on his side and all the following numbers on the other side of him.
The numbers on both sides added to exactly the same amount.
What was the number of the last house?
I have slightly changed the original wording and also took the liberty of coding a single 4 letter word of his text to avoid getting a trivial solution.
I ask for a solution which is over 45. The upper limit stays open.
So:
a. Provide an answer (or answers) 46 and up.
b. What word was replaced by XXXX?
Bonne chance!
(In reply to
Solution by Larry)
I agree, 'side of him' is not very clear.
I assumed he was standing on the street with lower numbers on one side, and higher ones on the other.
This could happen if, for example, one side was built up first and the other later.
Note: I have now found the original problem:
'A man said the house of his friend was in a long street, numbered on his
side one, two, three, and so on, and that all the numbers on one side of him
added up exactly the same as all the numbers on the other side of him. He
said he knew there were more than fifty houses on that side of the street, but
not so many as five hundred.
Can you discover the number of that house?'
So the original puzzle refers to the house, not the man, 'him' being short for 'his house'.
Edited on May 31, 2022, 10:07 am
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Posted by broll
on 2022-05-31 09:56:24 |
re: Solution
