All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Last Digit (Posted on 2004-01-23) Difficulty: 3 of 5
Find the last digit of summation of the series:
(1)^99 + (2)^99 + (3)^99 + (4)^99 + + (98)^99 + (99)^99

See The Solution Submitted by Ravi Raja    
Rating: 2.4000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts re(3): solution --- Gosh!!!.. | Comment 8 of 19 |
(In reply to re(2): solution --- Gosh!!!.. by Charlie)

right you are CHARLIE
Actually it is only the 5 that counts within a decade since 5+t and 5-t complement each other e.g. 2^3=8 8^3=2 8+2=0 (all taken mod 10) so go 1&9 3&7 4&6.... only 5 and 0 left.
ady
  Posted by Ady TZIDON on 2004-01-23 10:38:04

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information