Evaluate this definite integral:
n
∫ x2*(1+x4)-1 dx
1/n
where n is a real number greater than 1.
If you substitute u = 1/x
The limits become n to 1/n
The integrand becomes -(1+x^4)^-1
So the original integral is identical to what you get if you delete the x^2 term
∫ 1/n to n: (x^2)(1 + x^4)^(-1) dx
= ∫ 1/n to n: (1 + x^4)^(-1) dx
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Posted by Larry
on 2023-04-07 08:43:46 |