All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Diagonals Of A Polygon (Posted on 2004-01-31) Difficulty: 2 of 5
A polygon has 1325 diagonals. How many vertices does it have?

No Solution Yet Submitted by Ravi Raja    
Rating: 2.4167 (12 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Kind of simple... | Comment 13 of 16 |
The formula for diagonals is d = n(n-3)/2, where d is the # of diagonals, and n is the # of sides (or vertices). Just solve for n...

---Solve w/ the quadratic formula--- (I'm probably doing this more complicated than necessary, but I'm too tired to find a better way...)
And, since you can only use the positive root,
the figure as 53 vertices.

  Posted by Matt on 2004-12-08 03:26:27
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information