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Reciprocal Equation #8 (Posted on 2023-06-11) Difficulty: 2 of 5
Find all possible triplets (x, y, z) of positive integers that satisfy this equation:

(1+1/x)*(1+1/y)*(1+1/z) = 5

Prove that these are the only possible triplets in conformity with the given conditions.

Note: Computer program solutions are welcome, but an analytic solution is preferred.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution solution | Comment 2 of 4 |
The most that any two factors, such as (1+1/x)*(1+1/y), could amount to is 2*2 = 4, so the remaining factor, which could be any one of the three, has to be at least 5/4, so none of x, y or z could be larger than 4. Small enough to do with a calculator, but a computer is neater.

for x=sym(1:4)
  for y=sym(1:4)
    for z=sym(1:4)
      if (1+1/x)*(1+1/y)*(1+1/z)==5
        disp([x y z])
      end
    end
  end
end

shows only

[1, 1, 4]
[1, 4, 1]
[4, 1, 1]

meaning two of the three variables must be 1 and the third 4.

  Posted by Charlie on 2023-06-11 09:37:04
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