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Reciprocal Equation #8 (Posted on 2023-06-11) Difficulty: 2 of 5
Find all possible triplets (x, y, z) of positive integers that satisfy this equation:

(1+1/x)*(1+1/y)*(1+1/z) = 5

Prove that these are the only possible triplets in conformity with the given conditions.

Note: Computer program solutions are welcome, but an analytic solution is preferred.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Analytic solution | Comment 3 of 4 |
Order the unknowns so that x <= y <= z. Then 
1 + 1/x >= 1 + 1/y >= 1 + 1/z. Therefore 
(1 + 1/x)^3 >= 5 and x <= 1/(5^[1/3] - 1) < 1.41
Since x must be a positive integer, this gives x = 1

Next we have [(y + 1)/y] * [(z + 1)/z] = 5/2 
so [(y + 1)/y]^2 > 5/2. 
Therefore y <= 1/( [5/2]^.5 - 1 ) < 1.7
and since y must be a positive integer, this gives y = 1.

This leaves 
2 * 2 * (z+1)/z = 5. 
So that z = 4.

This is the sole solution.

  Posted by FrankM on 2023-06-11 12:07:34
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