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The Strange Behavior of i (Posted on 2023-06-26) Difficulty: 1 of 5
Let us consider a positive real number A.
For the imaginary number i, we know that: i*i = -1.
Therefore, i*i*i*i = (-1)*(-1)= 1
Hence, A*i*i*i*i = A
or √(A*i*i*i*i) = √A
or, √(A)*(i*i) = √A,
since sqrt(i*i*i*i) = i*i
or, - √(A) = √(A)

Provide a valid reason for this apparent inconsistency.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
solnSteven Lord2023-06-26 09:47:35
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