The two hands of a clock are so situated that, reckoning as minute points past XII, one is exactly the square of the distance of the other.

Determine all possible times that conform to the given conditions.

**** Adapted from an original problem by H. E. Dudeney.

(In reply to computer-aided solution by Charlie)

I seem to have neglected one second after 12. That's 1/60 of a minute, and the hour hand will be at 1/3600 of a minute interval away from the 12.

Posted by Charlie on 2023-09-12 10:37:46