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Easy as 1 2 3 (Posted on 2003-10-15) Difficulty: 3 of 5
In a game show, there is a game in which you have to order the value of three prizes in order of least expensive to most expensive. You have to get all three right in order to win.

The only problem is you have your spouse do all the shopping, so you only know that the first prize is between 500 and 2000, the second prize is between 1000 and 2500, and the third prize is between 1500 and 3000.

Which order should you put them in so that you have the highest probability of winning, and what is the probability that you will win using this arrangement?

See The Solution Submitted by Gamer    
Rating: 3.8333 (6 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Solution?Prab2003-11-05 22:07:57
re: Solution provisionsCharlie2003-10-20 11:41:08
QuestionSolution provisionsGamer2003-10-19 21:40:27
Simulation of differing distributionCharlie2003-10-16 09:33:12
re: The Price Is RightCharlie2003-10-16 08:52:08
The Price Is RightDan2003-10-16 08:24:27
Different distribution(s)Charlie2003-10-15 22:18:06
SolutionFull SolutionDJ2003-10-15 16:24:49
SolutionsolutionSilverKnight2003-10-15 15:38:08
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